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2011004130230 = 25201100413023
BaseRepresentation
bin11101010000111001001…
…011111101001110110110
321010020202100001120210222
4131100321023331032312
5230422014024131410
64135501553414342
7265201362032264
oct35207113751666
97106670046728
102011004130230
1170595344a797
122858b526a3b2
131178382a6934
146d494117434
153749e0d5955
hex1d4392fd3b6

2011004130230 has 8 divisors (see below), whose sum is σ = 3619807434432. Its totient is φ = 804401652088.

The previous prime is 2011004130181. The next prime is 2011004130241. The reversal of 2011004130230 is 320314001102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×20110041302302 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2011004130199 and 2011004130208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100550206502 + ... + 100550206521.

It is an arithmetic number, because the mean of its divisors is an integer number (452475929304).

Almost surely, 22011004130230 is an apocalyptic number.

2011004130230 is a deficient number, since it is larger than the sum of its proper divisors (1608803304202).

2011004130230 is a wasteful number, since it uses less digits than its factorization.

2011004130230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201100413030.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2011004130230 its reverse (320314001102), we get a palindrome (2331318131332).

The spelling of 2011004130230 in words is "two trillion, eleven billion, four million, one hundred thirty thousand, two hundred thirty".

Divisors: 1 2 5 10 201100413023 402200826046 1005502065115 2011004130230