Base | Representation |
---|---|
bin | 101101101110011001111001… |
… | …101011001100100100000111 |
3 | 222101001001211110120011201201 |
4 | 231232121321223030210013 |
5 | 202324314322011200403 |
6 | 1551412305110403331 |
7 | 60234032152621015 |
oct | 5556317153144407 |
9 | 871031743504651 |
10 | 201101000100103 |
11 | 59093500956354 |
12 | 1a67a87a060547 |
13 | 882998730aa5c |
14 | 37934a9c638b5 |
15 | 183b17274121d |
hex | b6e679acc907 |
201101000100103 has 8 divisors (see below), whose sum is σ = 203618788839872. Its totient is φ = 198592284473856.
The previous prime is 201101000100061. The next prime is 201101000100113. The reversal of 201101000100103 is 301001000101102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 201101000100103 - 225 = 201100966545671 is a prime.
It is a super-2 number, since 2×2011010001001032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 201101000100103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201101000100113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2268233775 + ... + 2268322432.
It is an arithmetic number, because the mean of its divisors is an integer number (25452348604984).
Almost surely, 2201101000100103 is an apocalyptic number.
201101000100103 is a deficient number, since it is larger than the sum of its proper divisors (2517788739769).
201101000100103 is an equidigital number, since it uses as much as digits as its factorization.
201101000100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4536556761.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 201101000100103 its reverse (301001000101102), we get a palindrome (502102000201205).
Subtracting 201101000100103 from its reverse (301001000101102), we obtain a palindrome (99900000000999).
The spelling of 201101000100103 in words is "two hundred one trillion, one hundred one billion, one hundred thousand, one hundred three".
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