201101000100113 has 2 divisors, whose sum is σ = 201101000100114. Its totient is φ = 201101000100112.

The previous prime is 201101000100061. The next prime is 201101000100131. The reversal of 201101000100113 is 311001000101102.

It is a happy number.

Together with next prime (201101000100131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200179259934784 + 921740165329 = 14148472^2 + 960073^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201101000100113 is a prime.

It is a super-2 number, since 2×201101000100113² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201101000100094 and 201101000100103.

It is not a weakly prime, because it can be changed into another prime (201101000100713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550500050056 + 100550500050057.

It is an arithmetic number, because the mean of its divisors is an integer number (100550500050057).

Almost surely, 2^{201101000100113} is an apocalyptic number.

It is an amenable number.

201101000100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201101000100113 is an equidigital number, since it uses as much as digits as its factorization.

201101000100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 201101000100113 its reverse (311001000101102), we get a palindrome (512102000201215).

The spelling of 201101000100113 in words is "two hundred one trillion, one hundred one billion, one hundred thousand, one hundred thirteen".