Base | Representation |
---|---|
bin | 101101101110011001111111… |
… | …101000101101000100111111 |
3 | 222101001002002102202012201021 |
4 | 231232121333220231010333 |
5 | 202324320023112011033 |
6 | 1551412323042125011 |
7 | 60234034505654332 |
oct | 5556317750550477 |
9 | 871032072665637 |
10 | 201101100110143 |
11 | 59093552354382 |
12 | 1a67a8a7650767 |
13 | 88299a1c55cac |
14 | 37934b9258619 |
15 | 183b17b3e8b2d |
hex | b6e67fa2d13f |
201101100110143 has 2 divisors, whose sum is σ = 201101100110144. Its totient is φ = 201101100110142.
The previous prime is 201101100110059. The next prime is 201101100110153. The reversal of 201101100110143 is 341011001101102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201101100110143 - 217 = 201101099979071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201101100110153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550550055071 + 100550550055072.
It is an arithmetic number, because the mean of its divisors is an integer number (100550550055072).
Almost surely, 2201101100110143 is an apocalyptic number.
201101100110143 is a deficient number, since it is larger than the sum of its proper divisors (1).
201101100110143 is an equidigital number, since it uses as much as digits as its factorization.
201101100110143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 201101100110143 its reverse (341011001101102), we get a palindrome (542112101211245).
The spelling of 201101100110143 in words is "two hundred one trillion, one hundred one billion, one hundred million, one hundred ten thousand, one hundred forty-three".
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