Base | Representation |
---|---|
bin | 1001001001010010001011… |
… | …11110111101001000110111 |
3 | 2122012111222011220221212202 |
4 | 10210221011332331020313 |
5 | 10113441203004324002 |
6 | 110434300422335115 |
7 | 4143625530120056 |
oct | 444510576751067 |
9 | 78174864827782 |
10 | 20110211011127 |
11 | 6453768930a06 |
12 | 23095b0b8a49b |
13 | b2b500421aa3 |
14 | 4d74a748c39d |
15 | 24d1a5760502 |
hex | 124a45fbd237 |
20110211011127 has 2 divisors, whose sum is σ = 20110211011128. Its totient is φ = 20110211011126.
The previous prime is 20110211011091. The next prime is 20110211011157. The reversal of 20110211011127 is 72111011201102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20110211011127 - 238 = 19835333104183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20110211011099 and 20110211011108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110211011157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055105505563 + 10055105505564.
It is an arithmetic number, because the mean of its divisors is an integer number (10055105505564).
Almost surely, 220110211011127 is an apocalyptic number.
20110211011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110211011127 is an equidigital number, since it uses as much as digits as its factorization.
20110211011127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 20110211011127 its reverse (72111011201102), we get a palindrome (92221222212229).
The spelling of 20110211011127 in words is "twenty trillion, one hundred ten billion, two hundred eleven million, eleven thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •