Base | Representation |
---|---|
bin | 1001001001010010001011… |
… | …11110111101110111011111 |
3 | 2122012111222011221002222021 |
4 | 10210221011332331313133 |
5 | 10113441203004422421 |
6 | 110434300422401011 |
7 | 4143625530131551 |
oct | 444510576756737 |
9 | 78174864832867 |
10 | 20110211014111 |
11 | 6453768933179 |
12 | 23095b0b90167 |
13 | b2b50042325a |
14 | 4d74a748d4d1 |
15 | 24d1a5761341 |
hex | 124a45fbdddf |
20110211014111 has 2 divisors, whose sum is σ = 20110211014112. Its totient is φ = 20110211014110.
The previous prime is 20110211014093. The next prime is 20110211014123. The reversal of 20110211014111 is 11141011201102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20110211014111 - 223 = 20110202625503 is a prime.
It is a super-2 number, since 2×201102110141112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110211014151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055105507055 + 10055105507056.
It is an arithmetic number, because the mean of its divisors is an integer number (10055105507056).
Almost surely, 220110211014111 is an apocalyptic number.
20110211014111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110211014111 is an equidigital number, since it uses as much as digits as its factorization.
20110211014111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 16.
Adding to 20110211014111 its reverse (11141011201102), we get a palindrome (31251222215213).
The spelling of 20110211014111 in words is "twenty trillion, one hundred ten billion, two hundred eleven million, fourteen thousand, one hundred eleven".
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