Base | Representation |
---|---|
bin | 1011101101001100011… |
… | …0001110011100010101 |
3 | 201020002201011122010212 |
4 | 2323103012032130111 |
5 | 11243333142321323 |
6 | 232215543455205 |
7 | 20346460550042 |
oct | 2732306163425 |
9 | 636081148125 |
10 | 201110120213 |
11 | 78321468a22 |
12 | 32b87457505 |
13 | 15c70304342 |
14 | 9a3b6d61c9 |
15 | 5370b58b78 |
hex | 2ed318e715 |
201110120213 has 2 divisors, whose sum is σ = 201110120214. Its totient is φ = 201110120212.
The previous prime is 201110120153. The next prime is 201110120221. The reversal of 201110120213 is 312021011102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126424335844 + 74685784369 = 355562^2 + 273287^2 .
It is a cyclic number.
It is not a de Polignac number, because 201110120213 - 26 = 201110120149 is a prime.
It is a super-3 number, since 3×2011101202133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201110120713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555060106 + 100555060107.
It is an arithmetic number, because the mean of its divisors is an integer number (100555060107).
Almost surely, 2201110120213 is an apocalyptic number.
It is an amenable number.
201110120213 is a deficient number, since it is larger than the sum of its proper divisors (1).
201110120213 is an equidigital number, since it uses as much as digits as its factorization.
201110120213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 201110120213 its reverse (312021011102), we get a palindrome (513131131315).
The spelling of 201110120213 in words is "two hundred one billion, one hundred ten million, one hundred twenty thousand, two hundred thirteen".
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