Base | Representation |
---|---|
bin | 11101010000111111000… |
… | …001011010100110100001 |
3 | 21010021000011021102101022 |
4 | 131100333001122212201 |
5 | 230422214104431431 |
6 | 4135515412015225 |
7 | 265203661130123 |
oct | 35207701324641 |
9 | 7107004242338 |
10 | 2011102030241 |
11 | 7059a3737497 |
12 | 285922001515 |
13 | 117852663635 |
14 | 6d4a311d213 |
15 | 374a79c307b |
hex | 1d43f05a9a1 |
2011102030241 has 2 divisors, whose sum is σ = 2011102030242. Its totient is φ = 2011102030240.
The previous prime is 2011102030213. The next prime is 2011102030243. The reversal of 2011102030241 is 1420302011102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1937444070241 + 73657960000 = 1391921^2 + 271400^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011102030241 - 26 = 2011102030177 is a prime.
Together with 2011102030243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2011102030243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005551015120 + 1005551015121.
It is an arithmetic number, because the mean of its divisors is an integer number (1005551015121).
Almost surely, 22011102030241 is an apocalyptic number.
It is an amenable number.
2011102030241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011102030241 is an equidigital number, since it uses as much as digits as its factorization.
2011102030241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2011102030241 its reverse (1420302011102), we get a palindrome (3431404041343).
The spelling of 2011102030241 in words is "two trillion, eleven billion, one hundred two million, thirty thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •