Base | Representation |
---|---|
bin | 10010101110101101… |
… | …110000110010101111 |
3 | 1220220120120210022102 |
4 | 102232231300302233 |
5 | 312141420213403 |
6 | 13123334405315 |
7 | 1311241352552 |
oct | 225655606257 |
9 | 56816523272 |
10 | 20111101103 |
11 | 8590212a15 |
12 | 3a9320083b |
13 | 1b86707232 |
14 | d8ad66699 |
15 | 7ca8b4b88 |
hex | 4aeb70caf |
20111101103 has 2 divisors, whose sum is σ = 20111101104. Its totient is φ = 20111101102.
The previous prime is 20111101069. The next prime is 20111101111. The reversal of 20111101103 is 30110111102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20111101103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111101193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055550551 + 10055550552.
It is an arithmetic number, because the mean of its divisors is an integer number (10055550552).
Almost surely, 220111101103 is an apocalyptic number.
20111101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111101103 is an equidigital number, since it uses as much as digits as its factorization.
20111101103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 20111101103 its reverse (30110111102), we get a palindrome (50221212205).
Subtracting 20111101103 from its reverse (30110111102), we obtain a palindrome (9999009999).
The spelling of 20111101103 in words is "twenty billion, one hundred eleven million, one hundred one thousand, one hundred three".
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