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201112210021213 is a prime number
BaseRepresentation
bin101101101110100100010101…
…110101101001101101011101
3222101002010202201000011121001
4231232210111311221231131
5202330010301231134323
61551421401314110301
760234610021441531
oct5556442565515535
9871063681004531
10201112210021213
1159098233632a67
121a680a8827b391
13882aa5288437a
143793c50979bc1
15183b5cb9493ad
hexb6e915d69b5d

201112210021213 has 2 divisors, whose sum is σ = 201112210021214. Its totient is φ = 201112210021212.

The previous prime is 201112210021201. The next prime is 201112210021223. The reversal of 201112210021213 is 312120012211102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196232272773849 + 4879937247364 = 14008293^2 + 2209058^2 .

It is a cyclic number.

It is not a de Polignac number, because 201112210021213 - 213 = 201112210013021 is a prime.

It is a super-2 number, since 2×2011122100212132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201112210021223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556105010606 + 100556105010607.

It is an arithmetic number, because the mean of its divisors is an integer number (100556105010607).

Almost surely, 2201112210021213 is an apocalyptic number.

It is an amenable number.

201112210021213 is a deficient number, since it is larger than the sum of its proper divisors (1).

201112210021213 is an equidigital number, since it uses as much as digits as its factorization.

201112210021213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 201112210021213 its reverse (312120012211102), we get a palindrome (513232222232315).

The spelling of 201112210021213 in words is "two hundred one trillion, one hundred twelve billion, two hundred ten million, twenty-one thousand, two hundred thirteen".