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201113009957 is a prime number
BaseRepresentation
bin1011101101001101000…
…1001111111100100101
3201020002220121110010102
42323103101033330211
511243334412304312
6232220125433445
720346524243666
oct2732321177445
9636086543112
10201113009957
1178323062042
1232b8840b885
1315c70aa6752
149a3bc4936d
155371029ec2
hex2ed344ff25

201113009957 has 2 divisors, whose sum is σ = 201113009958. Its totient is φ = 201113009956.

The previous prime is 201113009939. The next prime is 201113010023. The reversal of 201113009957 is 759900311102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113241672196 + 87871337761 = 336514^2 + 296431^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201113009957 is a prime.

It is a super-2 number, since 2×2011130099572 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 201113009957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201113009927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556504978 + 100556504979.

It is an arithmetic number, because the mean of its divisors is an integer number (100556504979).

Almost surely, 2201113009957 is an apocalyptic number.

It is an amenable number.

201113009957 is a deficient number, since it is larger than the sum of its proper divisors (1).

201113009957 is an equidigital number, since it uses as much as digits as its factorization.

201113009957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17010, while the sum is 38.

The spelling of 201113009957 in words is "two hundred one billion, one hundred thirteen million, nine thousand, nine hundred fifty-seven".