Base | Representation |
---|---|
bin | 1011101101001101001… |
… | …0000000111000101101 |
3 | 201020002220222122002201 |
4 | 2323103102000320231 |
5 | 11243334440213123 |
6 | 232220134021501 |
7 | 20346526040263 |
oct | 2732322007055 |
9 | 636086878081 |
10 | 201113210413 |
11 | 78323189705 |
12 | 32b884a7891 |
13 | 15c70b46a6b |
14 | 9a3bc9c433 |
15 | 53710695ad |
hex | 2ed3480e2d |
201113210413 has 2 divisors, whose sum is σ = 201113210414. Its totient is φ = 201113210412.
The previous prime is 201113210411. The next prime is 201113210429. The reversal of 201113210413 is 314012311102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 199396185444 + 1717024969 = 446538^2 + 41437^2 .
It is a cyclic number.
It is not a de Polignac number, because 201113210413 - 21 = 201113210411 is a prime.
It is a super-2 number, since 2×2011132104132 (a number of 23 digits) contains 22 as substring.
Together with 201113210411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201113210411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556605206 + 100556605207.
It is an arithmetic number, because the mean of its divisors is an integer number (100556605207).
Almost surely, 2201113210413 is an apocalyptic number.
It is an amenable number.
201113210413 is a deficient number, since it is larger than the sum of its proper divisors (1).
201113210413 is an equidigital number, since it uses as much as digits as its factorization.
201113210413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 201113210413 its reverse (314012311102), we get a palindrome (515125521515).
The spelling of 201113210413 in words is "two hundred one billion, one hundred thirteen million, two hundred ten thousand, four hundred thirteen".
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