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20112012121147 is a prime number
BaseRepresentation
bin1001001001010101100010…
…10101101001010000111011
32122012200121201000211100021
410210222301111221100323
510114003400100334042
6110435155242351311
74144021260236512
oct444526125512073
978180551024307
1020112012121147
116454502583591
122309a141bb537
13b2b72961016b
144d75d8773679
1524d25d937867
hex124ab156943b

20112012121147 has 2 divisors, whose sum is σ = 20112012121148. Its totient is φ = 20112012121146.

The previous prime is 20112012121141. The next prime is 20112012121153. The reversal of 20112012121147 is 74112121021102.

It is a balanced prime because it is at equal distance from previous prime (20112012121141) and next prime (20112012121153).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20112012121147 is a prime.

It is a super-2 number, since 2×201120121211472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20112012121141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056006060573 + 10056006060574.

It is an arithmetic number, because the mean of its divisors is an integer number (10056006060574).

Almost surely, 220112012121147 is an apocalyptic number.

20112012121147 is a deficient number, since it is larger than the sum of its proper divisors (1).

20112012121147 is an equidigital number, since it uses as much as digits as its factorization.

20112012121147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 25.

Adding to 20112012121147 its reverse (74112121021102), we get a palindrome (94224133142249).

The spelling of 20112012121147 in words is "twenty trillion, one hundred twelve billion, twelve million, one hundred twenty-one thousand, one hundred forty-seven".