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201121220213 is a prime number
BaseRepresentation
bin1011101101001111000…
…0100100011001110101
3201020010111001120110222
42323103300210121311
511243344013021323
6232221021424125
720346654110414
oct2732360443165
9636114046428
10201121220213
117832775a581
1232b8b10b045
1315c726bc7a4
149a3cd8547b
155371aec9c8
hex2ed3c24675

201121220213 has 2 divisors, whose sum is σ = 201121220214. Its totient is φ = 201121220212.

The previous prime is 201121220189. The next prime is 201121220231. The reversal of 201121220213 is 312022121102.

Together with next prime (201121220231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182583580804 + 18537639409 = 427298^2 + 136153^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201121220213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201121220191 and 201121220200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201121220243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560610106 + 100560610107.

It is an arithmetic number, because the mean of its divisors is an integer number (100560610107).

Almost surely, 2201121220213 is an apocalyptic number.

It is an amenable number.

201121220213 is a deficient number, since it is larger than the sum of its proper divisors (1).

201121220213 is an equidigital number, since it uses as much as digits as its factorization.

201121220213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 201121220213 its reverse (312022121102), we get a palindrome (513143341315).

The spelling of 201121220213 in words is "two hundred one billion, one hundred twenty-one million, two hundred twenty thousand, two hundred thirteen".