Base | Representation |
---|---|
bin | 1011101101001111010… |
… | …1001111001101010001 |
3 | 201020010120100202100121 |
4 | 2323103311033031101 |
5 | 11243344321202423 |
6 | 232221103550241 |
7 | 20350000365553 |
oct | 2732365171521 |
9 | 636116322317 |
10 | 201122444113 |
11 | 78328416068 |
12 | 32b8b5bb381 |
13 | 15c72a2a8a6 |
14 | 9a3d1c34d3 |
15 | 5371c9045d |
hex | 2ed3d4f351 |
201122444113 has 2 divisors, whose sum is σ = 201122444114. Its totient is φ = 201122444112.
The previous prime is 201122444111. The next prime is 201122444137. The reversal of 201122444113 is 311444221102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114255492289 + 86866951824 = 338017^2 + 294732^2 .
It is a cyclic number.
It is not a de Polignac number, because 201122444113 - 21 = 201122444111 is a prime.
Together with 201122444111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (201122444111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100561222056 + 100561222057.
It is an arithmetic number, because the mean of its divisors is an integer number (100561222057).
Almost surely, 2201122444113 is an apocalyptic number.
It is an amenable number.
201122444113 is a deficient number, since it is larger than the sum of its proper divisors (1).
201122444113 is an equidigital number, since it uses as much as digits as its factorization.
201122444113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 201122444113 its reverse (311444221102), we get a palindrome (512566665215).
The spelling of 201122444113 in words is "two hundred one billion, one hundred twenty-two million, four hundred forty-four thousand, one hundred thirteen".
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