Base | Representation |
---|---|
bin | 101101101110101110100000… |
… | …110010010001011011100111 |
3 | 222101010011221210221121022212 |
4 | 231232232200302101123213 |
5 | 202330200133030243301 |
6 | 1551430405122514035 |
7 | 60235444452215141 |
oct | 5556564062213347 |
9 | 871104853847285 |
10 | 201123131102951 |
11 | 590a1928269352 |
12 | 1a68301580591b |
13 | 882baa3339b05 |
14 | 37945a9185c91 |
15 | 183ba1a5ea4bb |
hex | b6eba0c916e7 |
201123131102951 has 2 divisors, whose sum is σ = 201123131102952. Its totient is φ = 201123131102950.
The previous prime is 201123131102897. The next prime is 201123131103049. The reversal of 201123131102951 is 159201131321102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201123131102951 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201123131162951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100561565551475 + 100561565551476.
It is an arithmetic number, because the mean of its divisors is an integer number (100561565551476).
Almost surely, 2201123131102951 is an apocalyptic number.
201123131102951 is a deficient number, since it is larger than the sum of its proper divisors (1).
201123131102951 is an equidigital number, since it uses as much as digits as its factorization.
201123131102951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 32.
The spelling of 201123131102951 in words is "two hundred one trillion, one hundred twenty-three billion, one hundred thirty-one million, one hundred two thousand, nine hundred fifty-one".
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