Base | Representation |
---|---|
bin | 10010101110111110… |
… | …101101001001111011 |
3 | 1220220212221102222012 |
4 | 102232332231021323 |
5 | 312144034331101 |
6 | 13124013520135 |
7 | 1311324201641 |
oct | 225676551173 |
9 | 56825842865 |
10 | 20115542651 |
11 | 8592776a16 |
12 | 3a947a304b |
13 | 1b87600a79 |
14 | d8b7a1191 |
15 | 7cae90bbb |
hex | 4aefad27b |
20115542651 has 2 divisors, whose sum is σ = 20115542652. Its totient is φ = 20115542650.
The previous prime is 20115542599. The next prime is 20115542683. The reversal of 20115542651 is 15624551102.
It is an a-pointer prime, because the next prime (20115542683) can be obtained adding 20115542651 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20115542651 is a prime.
It is a super-2 number, since 2×201155426512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20115542851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10057771325 + 10057771326.
It is an arithmetic number, because the mean of its divisors is an integer number (10057771326).
Almost surely, 220115542651 is an apocalyptic number.
20115542651 is a deficient number, since it is larger than the sum of its proper divisors (1).
20115542651 is an equidigital number, since it uses as much as digits as its factorization.
20115542651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 20115542651 in words is "twenty billion, one hundred fifteen million, five hundred forty-two thousand, six hundred fifty-one".
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