Base | Representation |
---|---|
bin | 1001001001100000001000… |
… | …10111101010000011000111 |
3 | 2122020020022010000100120212 |
4 | 10210300010113222003013 |
5 | 10114102022212443441 |
6 | 110441535512150035 |
7 | 4144312235412656 |
oct | 444600427520307 |
9 | 78206263010525 |
10 | 20117700124871 |
11 | 6456961286a08 |
12 | 230ab4109831b |
13 | b2c124b6aa3b |
14 | 4d79b7d6919d |
15 | 24d492e91eeb |
hex | 124c045ea0c7 |
20117700124871 has 2 divisors, whose sum is σ = 20117700124872. Its totient is φ = 20117700124870.
The previous prime is 20117700124853. The next prime is 20117700124909. The reversal of 20117700124871 is 17842100771102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20117700124871 - 210 = 20117700123847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20117700124831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058850062435 + 10058850062436.
It is an arithmetic number, because the mean of its divisors is an integer number (10058850062436).
Almost surely, 220117700124871 is an apocalyptic number.
20117700124871 is a deficient number, since it is larger than the sum of its proper divisors (1).
20117700124871 is an equidigital number, since it uses as much as digits as its factorization.
20117700124871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43904, while the sum is 41.
Adding to 20117700124871 its reverse (17842100771102), we get a palindrome (37959800895973).
The spelling of 20117700124871 in words is "twenty trillion, one hundred seventeen billion, seven hundred million, one hundred twenty-four thousand, eight hundred seventy-one".
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