Base | Representation |
---|---|
bin | 1001001001100100011100… |
… | …11010000111100001110101 |
3 | 2122020110021111210022022021 |
4 | 10210302032122013201311 |
5 | 10114121243100310332 |
6 | 110443001402033141 |
7 | 4144423516301326 |
oct | 444621632074165 |
9 | 78213244708267 |
10 | 20120016025717 |
11 | 645793a578553 |
12 | 230b4887a87b1 |
13 | b2c4038bc57a |
14 | 4d7b5777644d |
15 | 24d57b454c97 |
hex | 124c8e687875 |
20120016025717 has 2 divisors, whose sum is σ = 20120016025718. Its totient is φ = 20120016025716.
The previous prime is 20120016025709. The next prime is 20120016025721. The reversal of 20120016025717 is 71752061002102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18705227102116 + 1414788923601 = 4324954^2 + 1189449^2 .
It is a cyclic number.
It is not a de Polignac number, because 20120016025717 - 23 = 20120016025709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20120016025117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060008012858 + 10060008012859.
It is an arithmetic number, because the mean of its divisors is an integer number (10060008012859).
Almost surely, 220120016025717 is an apocalyptic number.
It is an amenable number.
20120016025717 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120016025717 is an equidigital number, since it uses as much as digits as its factorization.
20120016025717 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11760, while the sum is 34.
Adding to 20120016025717 its reverse (71752061002102), we get a palindrome (91872077027819).
The spelling of 20120016025717 in words is "twenty trillion, one hundred twenty billion, sixteen million, twenty-five thousand, seven hundred seventeen".
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