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201201012013 is a prime number
BaseRepresentation
bin1011101101100010000…
…0111100110100101101
3201020100001012102020211
42323120200330310231
511244024424341023
6232232551542421
720351643245521
oct2733040746455
9636301172224
10201201012013
11783687a9311
1232bb198aa11
1315c860a9181
149a497d5d81
155378b0ea0d
hex2ed883cd2d

201201012013 has 2 divisors, whose sum is σ = 201201012014. Its totient is φ = 201201012012.

The previous prime is 201201012007. The next prime is 201201012043. The reversal of 201201012013 is 310210102102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137891910244 + 63309101769 = 371338^2 + 251613^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201201012013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201201011984 and 201201012002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201201012043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600506006 + 100600506007.

It is an arithmetic number, because the mean of its divisors is an integer number (100600506007).

Almost surely, 2201201012013 is an apocalyptic number.

It is an amenable number.

201201012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

201201012013 is an equidigital number, since it uses as much as digits as its factorization.

201201012013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 201201012013 its reverse (310210102102), we get a palindrome (511411114115).

The spelling of 201201012013 in words is "two hundred one billion, two hundred one million, twelve thousand, thirteen".