Base | Representation |
---|---|
bin | 1001001001100100101000… |
… | …00101010000100101101111 |
3 | 2122020110112010220201211022 |
4 | 10210302110011100211233 |
5 | 10114121441433033403 |
6 | 110443015042244355 |
7 | 4144426053403025 |
oct | 444622405204557 |
9 | 78213463821738 |
10 | 20120111221103 |
11 | 6457989288223 |
12 | 230b4b46566bb |
13 | b2c41a5401ba |
14 | 4d7b66276715 |
15 | 24d5849aad38 |
hex | 124c9415096f |
20120111221103 has 2 divisors, whose sum is σ = 20120111221104. Its totient is φ = 20120111221102.
The previous prime is 20120111221087. The next prime is 20120111221129. The reversal of 20120111221103 is 30112211102102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20120111221103 - 24 = 20120111221087 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20120111221183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060055610551 + 10060055610552.
It is an arithmetic number, because the mean of its divisors is an integer number (10060055610552).
Almost surely, 220120111221103 is an apocalyptic number.
20120111221103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120111221103 is an equidigital number, since it uses as much as digits as its factorization.
20120111221103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 20120111221103 its reverse (30112211102102), we get a palindrome (50232322323205).
The spelling of 20120111221103 in words is "twenty trillion, one hundred twenty billion, one hundred eleven million, two hundred twenty-one thousand, one hundred three".
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