Base | Representation |
---|---|
bin | 1001001001100100101000… |
… | …01000010001101100001001 |
3 | 2122020110112012101220210022 |
4 | 10210302110020101230021 |
5 | 10114121442133341131 |
6 | 110443015111230225 |
7 | 4144426063205666 |
oct | 444622410215411 |
9 | 78213465356708 |
10 | 20120112012041 |
11 | 6457989778498 |
12 | 230b4b4978375 |
13 | b2c41a759202 |
14 | 4d7b66400a6d |
15 | 24d584ab537b |
hex | 124c94211b09 |
20120112012041 has 2 divisors, whose sum is σ = 20120112012042. Its totient is φ = 20120112012040.
The previous prime is 20120112011977. The next prime is 20120112012043. The reversal of 20120112012041 is 14021021102102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10207034574025 + 9913077438016 = 3194845^2 + 3148504^2 .
It is a cyclic number.
It is not a de Polignac number, because 20120112012041 - 26 = 20120112011977 is a prime.
Together with 20120112012043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20120112012043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060056006020 + 10060056006021.
It is an arithmetic number, because the mean of its divisors is an integer number (10060056006021).
Almost surely, 220120112012041 is an apocalyptic number.
It is an amenable number.
20120112012041 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120112012041 is an equidigital number, since it uses as much as digits as its factorization.
20120112012041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 20120112012041 its reverse (14021021102102), we get a palindrome (34141133114143).
The spelling of 20120112012041 in words is "twenty trillion, one hundred twenty billion, one hundred twelve million, twelve thousand, forty-one".
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