Base | Representation |
---|---|
bin | 101101101111110111111110… |
… | …011001100101101101000111 |
3 | 222101101201120002120201212222 |
4 | 231233313332121211231013 |
5 | 202332443204320231043 |
6 | 1551530532231002555 |
7 | 60244236254152001 |
oct | 5557677631455507 |
9 | 871351502521788 |
10 | 201202011102023 |
11 | 59122325a3a128 |
12 | 1a69636a50945b |
13 | 883636440a289 |
14 | 379832d297371 |
15 | 183dad55d1d68 |
hex | b6fdfe665b47 |
201202011102023 has 2 divisors, whose sum is σ = 201202011102024. Its totient is φ = 201202011102022.
The previous prime is 201202011101963. The next prime is 201202011102047. The reversal of 201202011102023 is 320201110202102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201202011102023 - 214 = 201202011085639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201202011101992 and 201202011102010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201202011102523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100601005551011 + 100601005551012.
It is an arithmetic number, because the mean of its divisors is an integer number (100601005551012).
Almost surely, 2201202011102023 is an apocalyptic number.
201202011102023 is a deficient number, since it is larger than the sum of its proper divisors (1).
201202011102023 is an equidigital number, since it uses as much as digits as its factorization.
201202011102023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 201202011102023 its reverse (320201110202102), we get a palindrome (521403121304125).
The spelling of 201202011102023 in words is "two hundred one trillion, two hundred two billion, eleven million, one hundred two thousand, twenty-three".
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