Base | Representation |
---|---|
bin | 11101010001111010100… |
… | …101000001111011001101 |
3 | 21010100120210102121220221 |
4 | 131101322211001323031 |
5 | 230431240403101333 |
6 | 4140202504111341 |
7 | 265240513123654 |
oct | 35217245017315 |
9 | 7110523377827 |
10 | 2012101222093 |
11 | 706366759086 |
12 | 285b60765551 |
13 | 117981679a11 |
14 | 6d559ada19b |
15 | 37515594d2d |
hex | 1d47a941ecd |
2012101222093 has 2 divisors, whose sum is σ = 2012101222094. Its totient is φ = 2012101222092.
The previous prime is 2012101222081. The next prime is 2012101222129. The reversal of 2012101222093 is 3902221012102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2011668498889 + 432723204 = 1418333^2 + 20802^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2012101222093 is a prime.
It is a super-2 number, since 2×20121012220932 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012101222693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006050611046 + 1006050611047.
It is an arithmetic number, because the mean of its divisors is an integer number (1006050611047).
Almost surely, 22012101222093 is an apocalyptic number.
It is an amenable number.
2012101222093 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012101222093 is an equidigital number, since it uses as much as digits as its factorization.
2012101222093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 2012101222093 its reverse (3902221012102), we get a palindrome (5914322234195).
The spelling of 2012101222093 in words is "two trillion, twelve billion, one hundred one million, two hundred twenty-two thousand, ninety-three".
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