201211010081 has 2 divisors, whose sum is σ = 201211010082. Its totient is φ = 201211010080.

The previous prime is 201211009931. The next prime is 201211010083. The reversal of 201211010081 is 180010112102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 173714737681 + 27496272400 = 416791^2 + 165820^2 .

It is a cyclic number.

It is not a de Polignac number, because 201211010081 - 2¹⁰ = 201211009057 is a prime.

It is a super-2 number, since 2×201211010081² (a number of 23 digits) contains 22 as substring.

Together with 201211010083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (201211010083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605505040 + 100605505041.

It is an arithmetic number, because the mean of its divisors is an integer number (100605505041).

Almost surely, 2^201211010081 is an apocalyptic number.

It is an amenable number.

201211010081 is a deficient number, since it is larger than the sum of its proper divisors (1).

201211010081 is an equidigital number, since it uses as much as digits as its factorization.

201211010081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 201211010081 its reverse (180010112102), we get a palindrome (381221122183).

The spelling of 201211010081 in words is "two hundred one billion, two hundred eleven million, ten thousand, eighty-one".