Base | Representation |
---|---|
bin | 11101010001111011000… |
… | …111010001110100100101 |
3 | 21010100121102022202102202 |
4 | 131101323013101310211 |
5 | 230431300202400401 |
6 | 4140203424344245 |
7 | 265240652335631 |
oct | 35217307216445 |
9 | 7110542282382 |
10 | 2012110200101 |
11 | 706370830421 |
12 | 285b63775085 |
13 | 1179834a1351 |
14 | 6d55ad95dc1 |
15 | 3751626a06b |
hex | 1d47b1d1d25 |
2012110200101 has 2 divisors, whose sum is σ = 2012110200102. Its totient is φ = 2012110200100.
The previous prime is 2012110200077. The next prime is 2012110200103. The reversal of 2012110200101 is 1010020112102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1523432307076 + 488677893025 = 1234274^2 + 699055^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2012110200101 is a prime.
Together with 2012110200103, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012110200103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055100050 + 1006055100051.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055100051).
Almost surely, 22012110200101 is an apocalyptic number.
It is an amenable number.
2012110200101 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012110200101 is an equidigital number, since it uses as much as digits as its factorization.
2012110200101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 2012110200101 its reverse (1010020112102), we get a palindrome (3022130312203).
The spelling of 2012110200101 in words is "two trillion, twelve billion, one hundred ten million, two hundred thousand, one hundred one".
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