Base | Representation |
---|---|
bin | 11101010001111011111… |
… | …001110101101001000001 |
3 | 21010100122100021010101112 |
4 | 131101323321311221001 |
5 | 230431312101012032 |
6 | 4140205020413105 |
7 | 265241203110035 |
oct | 35217371655101 |
9 | 7110570233345 |
10 | 2012123454017 |
11 | 706378263276 |
12 | 285b680a7195 |
13 | 117986161cc1 |
14 | 6d55ca461c5 |
15 | 375174d71b2 |
hex | 1d47be75a41 |
2012123454017 has 2 divisors, whose sum is σ = 2012123454018. Its totient is φ = 2012123454016.
The previous prime is 2012123453987. The next prime is 2012123454031. The reversal of 2012123454017 is 7104543212102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1229861038081 + 782262415936 = 1108991^2 + 884456^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012123454017 - 216 = 2012123388481 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012123454067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006061727008 + 1006061727009.
It is an arithmetic number, because the mean of its divisors is an integer number (1006061727009).
Almost surely, 22012123454017 is an apocalyptic number.
It is an amenable number.
2012123454017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012123454017 is an equidigital number, since it uses as much as digits as its factorization.
2012123454017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 2012123454017 its reverse (7104543212102), we get a palindrome (9116666666119).
The spelling of 2012123454017 in words is "two trillion, twelve billion, one hundred twenty-three million, four hundred fifty-four thousand, seventeen".
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