Base | Representation |
---|---|
bin | 11101010001111011111… |
… | …100101110101110101111 |
3 | 21010100122101200122100021 |
4 | 131101323330232232233 |
5 | 230431312244242033 |
6 | 4140205044543011 |
7 | 265241212415233 |
oct | 35217374565657 |
9 | 7110571618307 |
10 | 2012124212143 |
11 | 706378730921 |
12 | 285b683b1a67 |
13 | 1179863690b6 |
14 | 6d55cba25c3 |
15 | 375175d6b2d |
hex | 1d47bf2ebaf |
2012124212143 has 2 divisors, whose sum is σ = 2012124212144. Its totient is φ = 2012124212142.
The previous prime is 2012124212089. The next prime is 2012124212207. The reversal of 2012124212143 is 3412124212102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012124212143 - 213 = 2012124203951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012124212543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006062106071 + 1006062106072.
It is an arithmetic number, because the mean of its divisors is an integer number (1006062106072).
Almost surely, 22012124212143 is an apocalyptic number.
2012124212143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012124212143 is an equidigital number, since it uses as much as digits as its factorization.
2012124212143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2012124212143 its reverse (3412124212102), we get a palindrome (5424248424245).
The spelling of 2012124212143 in words is "two trillion, twelve billion, one hundred twenty-four million, two hundred twelve thousand, one hundred forty-three".
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