Base | Representation |
---|---|
bin | 101101110000001001101010… |
… | …010110100000000111111111 |
3 | 222101110112120121111110021121 |
4 | 231300021222112200013333 |
5 | 202333301103014214442 |
6 | 1551543352514011411 |
7 | 60245511005036452 |
oct | 5560115226400777 |
9 | 871415517443247 |
10 | 201221002101247 |
11 | 5912a390957a07 |
12 | 1a699b8a576b67 |
13 | 883809ca45c1b |
14 | 379921156b499 |
15 | 183e34798e967 |
hex | b7026a5a01ff |
201221002101247 has 2 divisors, whose sum is σ = 201221002101248. Its totient is φ = 201221002101246.
The previous prime is 201221002101199. The next prime is 201221002101271. The reversal of 201221002101247 is 742101200122102.
201221002101247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201221002101247 - 223 = 201220993712639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201221002101277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100610501050623 + 100610501050624.
It is an arithmetic number, because the mean of its divisors is an integer number (100610501050624).
Almost surely, 2201221002101247 is an apocalyptic number.
201221002101247 is a deficient number, since it is larger than the sum of its proper divisors (1).
201221002101247 is an equidigital number, since it uses as much as digits as its factorization.
201221002101247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 201221002101247 its reverse (742101200122102), we get a palindrome (943322202223349).
The spelling of 201221002101247 in words is "two hundred one trillion, two hundred twenty-one billion, two million, one hundred one thousand, two hundred forty-seven".
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