Base | Representation |
---|---|
bin | 11101010010000001001… |
… | …000010001101101011111 |
3 | 21010100212110020021111012 |
4 | 131102001020101231133 |
5 | 230432002022000322 |
6 | 4140221431445435 |
7 | 265243316232602 |
oct | 35220110215537 |
9 | 7110773207435 |
10 | 2012211125087 |
11 | 7064127a38a9 |
12 | 285b9152687b |
13 | 11799b379b87 |
14 | 6d56a548339 |
15 | 37520053ae2 |
hex | 1d481211b5f |
2012211125087 has 2 divisors, whose sum is σ = 2012211125088. Its totient is φ = 2012211125086.
The previous prime is 2012211125069. The next prime is 2012211125101. The reversal of 2012211125087 is 7805211122102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012211125087 - 220 = 2012210076511 is a prime.
It is a super-2 number, since 2×20122111250872 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012211125027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006105562543 + 1006105562544.
It is an arithmetic number, because the mean of its divisors is an integer number (1006105562544).
Almost surely, 22012211125087 is an apocalyptic number.
2012211125087 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012211125087 is an equidigital number, since it uses as much as digits as its factorization.
2012211125087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4480, while the sum is 32.
Adding to 2012211125087 its reverse (7805211122102), we get a palindrome (9817422247189).
The spelling of 2012211125087 in words is "two trillion, twelve billion, two hundred eleven million, one hundred twenty-five thousand, eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •