Base | Representation |
---|---|
bin | 1001001001101000111100… |
… | …11110100111011010011111 |
3 | 2122020200111221222121210212 |
4 | 10210310132132213122133 |
5 | 10114141220334431444 |
6 | 110444041304523035 |
7 | 4144540436300153 |
oct | 444643636473237 |
9 | 78220457877725 |
10 | 20122433123999 |
11 | 645896a9a9238 |
12 | 230ba4218047b |
13 | b2c6ca5b393b |
14 | 4d7d067a7063 |
15 | 24d66d75719e |
hex | 124d1e7a769f |
20122433123999 has 2 divisors, whose sum is σ = 20122433124000. Its totient is φ = 20122433123998.
The previous prime is 20122433123987. The next prime is 20122433124011. The reversal of 20122433123999 is 99932133422102.
It is a balanced prime because it is at equal distance from previous prime (20122433123987) and next prime (20122433124011).
It is a cyclic number.
It is not a de Polignac number, because 20122433123999 - 224 = 20122416346783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20122433123929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061216561999 + 10061216562000.
It is an arithmetic number, because the mean of its divisors is an integer number (10061216562000).
Almost surely, 220122433123999 is an apocalyptic number.
20122433123999 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122433123999 is an equidigital number, since it uses as much as digits as its factorization.
20122433123999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 20122433123999 in words is "twenty trillion, one hundred twenty-two billion, four hundred thirty-three million, one hundred twenty-three thousand, nine hundred ninety-nine".
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