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2012396092397 is a prime number
BaseRepresentation
bin11101010010001100001…
…001110111101111101101
321010101100100021120221022
4131102030021313233231
5230432341344424042
64140252040143525
7265251023360105
oct35221411675755
97111310246838
102012396092397
117064a8149549
12286023467ba5
131179ca79c9a2
146d586d36205
15375313ddcd2
hex1d48c277bed

2012396092397 has 2 divisors, whose sum is σ = 2012396092398. Its totient is φ = 2012396092396.

The previous prime is 2012396092379. The next prime is 2012396092451. The reversal of 2012396092397 is 7932906932102.

Together with previous prime (2012396092379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1681018564681 + 331377527716 = 1296541^2 + 575654^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012396092397 - 212 = 2012396088301 is a prime.

It is a super-2 number, since 2×20123960923972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012396092367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006198046198 + 1006198046199.

It is an arithmetic number, because the mean of its divisors is an integer number (1006198046199).

Almost surely, 22012396092397 is an apocalyptic number.

It is an amenable number.

2012396092397 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012396092397 is an equidigital number, since it uses as much as digits as its factorization.

2012396092397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2204496, while the sum is 53.

The spelling of 2012396092397 in words is "two trillion, twelve billion, three hundred ninety-six million, ninety-two thousand, three hundred ninety-seven".