Base | Representation |
---|---|
bin | 1001001001101110101110… |
… | …11100100010011010111001 |
3 | 2122020222112020021120002202 |
4 | 10210313113130202122321 |
5 | 10114214044302123332 |
6 | 110445313242035545 |
7 | 4145010360351554 |
oct | 444672734423271 |
9 | 78228466246082 |
10 | 20125536364217 |
11 | 645a212673579 |
12 | 23105694a8bb5 |
13 | b2caa34a475b |
14 | 4d811c9a569b |
15 | 24d7a0de0a62 |
hex | 124dd77226b9 |
20125536364217 has 2 divisors, whose sum is σ = 20125536364218. Its totient is φ = 20125536364216.
The previous prime is 20125536364169. The next prime is 20125536364253. The reversal of 20125536364217 is 71246363552102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13278998369296 + 6846537994921 = 3644036^2 + 2616589^2 .
It is a cyclic number.
It is not a de Polignac number, because 20125536364217 - 212 = 20125536360121 is a prime.
It is not a weakly prime, because it can be changed into another prime (20125536364277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062768182108 + 10062768182109.
It is an arithmetic number, because the mean of its divisors is an integer number (10062768182109).
Almost surely, 220125536364217 is an apocalyptic number.
It is an amenable number.
20125536364217 is a deficient number, since it is larger than the sum of its proper divisors (1).
20125536364217 is an equidigital number, since it uses as much as digits as its factorization.
20125536364217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 47.
The spelling of 20125536364217 in words is "twenty trillion, one hundred twenty-five billion, five hundred thirty-six million, three hundred sixty-four thousand, two hundred seventeen".
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