Base | Representation |
---|---|
bin | 1001001001110001101101… |
… | …01111011001001100101111 |
3 | 2122021010122122122220212202 |
4 | 10210320312233121030233 |
5 | 10114230333044031303 |
6 | 110450140033252115 |
7 | 4145065112633411 |
oct | 444706657311457 |
9 | 78233578586782 |
10 | 20127135142703 |
11 | 645a963090506 |
12 | 2310934a0403b |
13 | b2cc997a0524 |
14 | 4d823105c9b1 |
15 | 24d84644cc88 |
hex | 124e36bd932f |
20127135142703 has 2 divisors, whose sum is σ = 20127135142704. Its totient is φ = 20127135142702.
The previous prime is 20127135142637. The next prime is 20127135142711. The reversal of 20127135142703 is 30724153172102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20127135142703 - 222 = 20127130948399 is a prime.
It is a super-2 number, since 2×201271351427032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20127135142753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10063567571351 + 10063567571352.
It is an arithmetic number, because the mean of its divisors is an integer number (10063567571352).
Almost surely, 220127135142703 is an apocalyptic number.
20127135142703 is a deficient number, since it is larger than the sum of its proper divisors (1).
20127135142703 is an equidigital number, since it uses as much as digits as its factorization.
20127135142703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 70560, while the sum is 38.
The spelling of 20127135142703 in words is "twenty trillion, one hundred twenty-seven billion, one hundred thirty-five million, one hundred forty-two thousand, seven hundred three".
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