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2013002320117 is a prime number
BaseRepresentation
bin11101010010110000010…
…010011100100011110101
321010102220121000011000211
4131102300102130203311
5230440112043220432
64140432133505421
7265302034254625
oct35226022344365
97112817004024
102013002320117
11706789370398
122861724a2271
13117a96269109
146d603660885
153756973bd47
hex1d4b049c8f5

2013002320117 has 2 divisors, whose sum is σ = 2013002320118. Its totient is φ = 2013002320116.

The previous prime is 2013002319971. The next prime is 2013002320129. The reversal of 2013002320117 is 7110232003102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1640958438001 + 372043882116 = 1280999^2 + 609954^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013002320117 - 219 = 2013001795829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013002327117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006501160058 + 1006501160059.

It is an arithmetic number, because the mean of its divisors is an integer number (1006501160059).

Almost surely, 22013002320117 is an apocalyptic number.

It is an amenable number.

2013002320117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013002320117 is an equidigital number, since it uses as much as digits as its factorization.

2013002320117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 22.

Adding to 2013002320117 its reverse (7110232003102), we get a palindrome (9123234323219).

The spelling of 2013002320117 in words is "two trillion, thirteen billion, two million, three hundred twenty thousand, one hundred seventeen".