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2013003100000 = 2555296531063
BaseRepresentation
bin11101010010110000010…
…101011010111101100000
321010102220122110202211101
4131102300111122331200
5230440112243200000
64140432202324144
7265302044013424
oct35226025327540
97112818422741
102013003100000
11706789853322
122861727b9654
13117a96480099
146d6037c4b84
1537569842e6a
hex1d4b055af60

2013003100000 has 288 divisors, whose sum is σ = 5137045583040. Its totient is φ = 775514880000.

The previous prime is 2013003099973. The next prime is 2013003100019. The reversal of 2013003100000 is 13003102.

It is a super-2 number, since 2×20130031000002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 2013003100000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1893699469 + ... + 1893700531.

It is an arithmetic number, because the mean of its divisors is an integer number (17836963830).

Almost surely, 22013003100000 is an apocalyptic number.

2013003100000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013003100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2568522791520).

2013003100000 is an abundant number, since it is smaller than the sum of its proper divisors (3124042483040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013003100000 is an equidigital number, since it uses as much as digits as its factorization.

2013003100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1780 (or 1752 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 2013003100000 its reverse (13003102), we get a palindrome (2013016103102).

The spelling of 2013003100000 in words is "two trillion, thirteen billion, three million, one hundred thousand".