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20130031354453 is a prime number
BaseRepresentation
bin1001001001110111000110…
…10111100100001001010101
32122021102010111101201111121
410210323203113210021111
510114302301011320303
6110451335253203541
74145226641215426
oct444734327441125
978242114351447
1020130031354453
116461109a02239
1223114029305b1
13b3033b815ba7
144d842796964d
1524d96583e9bd
hex124ee35e4255

20130031354453 has 2 divisors, whose sum is σ = 20130031354454. Its totient is φ = 20130031354452.

The previous prime is 20130031354441. The next prime is 20130031354481. The reversal of 20130031354453 is 35445313003102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11284177611249 + 8845853743204 = 3359193^2 + 2974198^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130031354453 - 29 = 20130031353941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130031354423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065015677226 + 10065015677227.

It is an arithmetic number, because the mean of its divisors is an integer number (10065015677227).

Almost surely, 220130031354453 is an apocalyptic number.

It is an amenable number.

20130031354453 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130031354453 is an equidigital number, since it uses as much as digits as its factorization.

20130031354453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 20130031354453 its reverse (35445313003102), we get a palindrome (55575344357555).

The spelling of 20130031354453 in words is "twenty trillion, one hundred thirty billion, thirty-one million, three hundred fifty-four thousand, four hundred fifty-three".