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20130033032341 is a prime number
BaseRepresentation
bin1001001001110111000110…
…11101111101110010010101
32122021102010121112222010121
410210323203131331302111
510114302301424013331
6110451335353151541
74145226661404301
oct444734335756225
978242117488117
1020130033032341
11646110a948921
1223114033bb5b1
13b3033bc8281b
144d8427c84d01
1524d965a71c11
hex124ee377dc95

20130033032341 has 2 divisors, whose sum is σ = 20130033032342. Its totient is φ = 20130033032340.

The previous prime is 20130033032299. The next prime is 20130033032357. The reversal of 20130033032341 is 14323033003102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13906529889316 + 6223503143025 = 3729146^2 + 2494695^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130033032341 - 225 = 20129999477909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130033032381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065016516170 + 10065016516171.

It is an arithmetic number, because the mean of its divisors is an integer number (10065016516171).

Almost surely, 220130033032341 is an apocalyptic number.

It is an amenable number.

20130033032341 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130033032341 is an equidigital number, since it uses as much as digits as its factorization.

20130033032341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 20130033032341 its reverse (14323033003102), we get a palindrome (34453066035443).

The spelling of 20130033032341 in words is "twenty trillion, one hundred thirty billion, thirty-three million, thirty-two thousand, three hundred forty-one".