20130102011021 has 2 divisors, whose sum is σ = 20130102011022. Its totient is φ = 20130102011020.

The previous prime is 20130102010979. The next prime is 20130102011029. The reversal of 20130102011021 is 12011020103102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20075677786921 + 54424224100 = 4480589^2 + 233290^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20130102011021 is a prime.

It is a super-2 number, since 2×20130102011021² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20130102010987 and 20130102011005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130102011029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065051005510 + 10065051005511.

It is an arithmetic number, because the mean of its divisors is an integer number (10065051005511).

Almost surely, 2^{20130102011021} is an apocalyptic number.

It is an amenable number.

20130102011021 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130102011021 is an equidigital number, since it uses as much as digits as its factorization.

20130102011021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 20130102011021 its reverse (12011020103102), we get a palindrome (32141122114123).

The spelling of 20130102011021 in words is "twenty trillion, one hundred thirty billion, one hundred two million, eleven thousand, twenty-one".