Base | Representation |
---|---|
bin | 101101110001010100001011… |
… | …111010100101011100100010 |
3 | 222101202012010100020201222110 |
4 | 231301110023322211130202 |
5 | 202341103443124301310 |
6 | 1552044225104220150 |
7 | 60254342661606252 |
oct | 5561241372453442 |
9 | 871665110221873 |
10 | 201301022103330 |
11 | 59160314085936 |
12 | 1a6b15a100a656 |
13 | 88427b3062096 |
14 | 379d042c31962 |
15 | 184147caaed20 |
hex | b7150bea5722 |
201301022103330 has 32 divisors (see below), whose sum is σ = 483338422119744. Its totient is φ = 53656275997376.
The previous prime is 201301022103299. The next prime is 201301022103341. The reversal of 201301022103330 is 33301220103102.
201301022103330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 201301022103297 and 201301022103306.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1499716992 + ... + 1499851211.
It is an arithmetic number, because the mean of its divisors is an integer number (15104325691242).
Almost surely, 2201301022103330 is an apocalyptic number.
201301022103330 is an abundant number, since it is smaller than the sum of its proper divisors (282037400016414).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201301022103330 is a wasteful number, since it uses less digits than its factorization.
201301022103330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2999570450.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 201301022103330 its reverse (33301220103102), we get a palindrome (234602242206432).
The spelling of 201301022103330 in words is "two hundred one trillion, three hundred one billion, twenty-two million, one hundred three thousand, three hundred thirty".
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