20130122021 has 2 divisors, whose sum is σ = 20130122022. Its totient is φ = 20130122020.

The previous prime is 20130121969. The next prime is 20130122063. The reversal of 20130122021 is 12022103102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17466529921 + 2663592100 = 132161^2 + 51610^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20130122021 is a prime.

It is a super-3 number, since 3×20130122021³ (a number of 32 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20130121987 and 20130122005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130121021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065061010 + 10065061011.

It is an arithmetic number, because the mean of its divisors is an integer number (10065061011).

Almost surely, 2^20130122021 is an apocalyptic number.

It is an amenable number.

20130122021 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130122021 is an equidigital number, since it uses as much as digits as its factorization.

20130122021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 20130122021 its reverse (12022103102), we get a palindrome (32152225123).

It can be divided in two parts, 201301 and 22021, that added together give a palindrome (223322).

The spelling of 20130122021 in words is "twenty billion, one hundred thirty million, one hundred twenty-two thousand, twenty-one".