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20130201012023 is a prime number
BaseRepresentation
bin1001001001110111011010…
…11110110000011100110111
32122021102120022122012221022
410210323231132300130313
510114303122424341043
6110451404153411355
74145234101250054
oct444735536603467
978242508565838
1020130201012023
116461196750503
12231144b709b5b
13b30367a0839b
144d84422d002b
1524d9756a3868
hex124eed7b0737

20130201012023 has 2 divisors, whose sum is σ = 20130201012024. Its totient is φ = 20130201012022.

The previous prime is 20130201012001. The next prime is 20130201012059. The reversal of 20130201012023 is 32021010203102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20130201012023 - 212 = 20130201007927 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20130201011992 and 20130201012010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130201012923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100506011 + 10065100506012.

It is an arithmetic number, because the mean of its divisors is an integer number (10065100506012).

Almost surely, 220130201012023 is an apocalyptic number.

20130201012023 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130201012023 is an equidigital number, since it uses as much as digits as its factorization.

20130201012023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 20130201012023 its reverse (32021010203102), we get a palindrome (52151211215125).

The spelling of 20130201012023 in words is "twenty trillion, one hundred thirty billion, two hundred one million, twelve thousand, twenty-three".