Base | Representation |
---|---|
bin | 1001001001110111011010… |
… | …11110110000011100110111 |
3 | 2122021102120022122012221022 |
4 | 10210323231132300130313 |
5 | 10114303122424341043 |
6 | 110451404153411355 |
7 | 4145234101250054 |
oct | 444735536603467 |
9 | 78242508565838 |
10 | 20130201012023 |
11 | 6461196750503 |
12 | 231144b709b5b |
13 | b30367a0839b |
14 | 4d84422d002b |
15 | 24d9756a3868 |
hex | 124eed7b0737 |
20130201012023 has 2 divisors, whose sum is σ = 20130201012024. Its totient is φ = 20130201012022.
The previous prime is 20130201012001. The next prime is 20130201012059. The reversal of 20130201012023 is 32021010203102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20130201012023 - 212 = 20130201007927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20130201011992 and 20130201012010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130201012923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100506011 + 10065100506012.
It is an arithmetic number, because the mean of its divisors is an integer number (10065100506012).
Almost surely, 220130201012023 is an apocalyptic number.
20130201012023 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130201012023 is an equidigital number, since it uses as much as digits as its factorization.
20130201012023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 20130201012023 its reverse (32021010203102), we get a palindrome (52151211215125).
The spelling of 20130201012023 in words is "twenty trillion, one hundred thirty billion, two hundred one million, twelve thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •