Base | Representation |
---|---|
bin | 1001001001110111011110… |
… | …11001111110011101001101 |
3 | 2122021102122120102021200112 |
4 | 10210323233121332131031 |
5 | 10114303204212004401 |
6 | 110451411310005405 |
7 | 4145234642641232 |
oct | 444735731763515 |
9 | 78242576367615 |
10 | 20130233313101 |
11 | 6461202a0280a |
12 | 231145a4a6865 |
13 | b30371607852 |
14 | 4d84466db789 |
15 | 24d9784343bb |
hex | 124eef67e74d |
20130233313101 has 2 divisors, whose sum is σ = 20130233313102. Its totient is φ = 20130233313100.
The previous prime is 20130233313097. The next prime is 20130233313121. The reversal of 20130233313101 is 10131333203102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15629577137476 + 4500656175625 = 3953426^2 + 2121475^2 .
It is a cyclic number.
It is not a de Polignac number, because 20130233313101 - 22 = 20130233313097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130233313121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065116656550 + 10065116656551.
It is an arithmetic number, because the mean of its divisors is an integer number (10065116656551).
Almost surely, 220130233313101 is an apocalyptic number.
It is an amenable number.
20130233313101 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130233313101 is an equidigital number, since it uses as much as digits as its factorization.
20130233313101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 20130233313101 its reverse (10131333203102), we get a palindrome (30261566516203).
The spelling of 20130233313101 in words is "twenty trillion, one hundred thirty billion, two hundred thirty-three million, three hundred thirteen thousand, one hundred one".
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