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201303311317 is a prime number
BaseRepresentation
bin1011101101111010011…
…1001100001111010101
3201020121011200202111221
42323132213030033111
511244232121430232
6232251044330341
720354324625313
oct2733647141725
9636534622457
10201303311317
1178410520299
12330200a39b1
1315ca13463c4
149a592250b3
155382aba897
hex2ede9cc3d5

201303311317 has 2 divisors, whose sum is σ = 201303311318. Its totient is φ = 201303311316.

The previous prime is 201303311281. The next prime is 201303311323. The reversal of 201303311317 is 713113303102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139643468721 + 61659842596 = 373689^2 + 248314^2 .

It is a cyclic number.

It is not a de Polignac number, because 201303311317 - 211 = 201303309269 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201303311291 and 201303311300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201303311327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651655658 + 100651655659.

It is an arithmetic number, because the mean of its divisors is an integer number (100651655659).

Almost surely, 2201303311317 is an apocalyptic number.

It is an amenable number.

201303311317 is a deficient number, since it is larger than the sum of its proper divisors (1).

201303311317 is an equidigital number, since it uses as much as digits as its factorization.

201303311317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 25.

Adding to 201303311317 its reverse (713113303102), we get a palindrome (914416614419).

The spelling of 201303311317 in words is "two hundred one billion, three hundred three million, three hundred eleven thousand, three hundred seventeen".