2013102101011 has 2 divisors, whose sum is σ = 2013102101012. Its totient is φ = 2013102101010.

The previous prime is 2013102101009. The next prime is 2013102101039. The reversal of 2013102101011 is 1101012013102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013102101011 - 2¹ = 2013102101009 is a prime.

Together with 2013102101009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2013102100982 and 2013102101000.

It is not a weakly prime, because it can be changed into another prime (2013102101051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006551050505 + 1006551050506.

It is an arithmetic number, because the mean of its divisors is an integer number (1006551050506).

Almost surely, 2^{2013102101011} is an apocalyptic number.

2013102101011 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013102101011 is an equidigital number, since it uses as much as digits as its factorization.

2013102101011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 2013102101011 its reverse (1101012013102), we get a palindrome (3114114114113).

The spelling of 2013102101011 in words is "two trillion, thirteen billion, one hundred two million, one hundred one thousand, eleven".