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20131030011011 is a prime number
BaseRepresentation
bin1001001001111000111101…
…11001001000110010000011
32122021111201002112201202112
410210330132321020302003
510114311322140323021
6110452022330005535
74145263455522533
oct444743671106203
978244632481675
1020131030011011
116461581698737
1223116412768ab
13b3046a6a272a
144d84c04474c3
1524d9c3357d5b
hex124f1ee48c83

20131030011011 has 2 divisors, whose sum is σ = 20131030011012. Its totient is φ = 20131030011010.

The previous prime is 20131030010989. The next prime is 20131030011013. The reversal of 20131030011011 is 11011003013102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20131030011011 - 214 = 20131029994627 is a prime.

Together with 20131030011013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20131030011013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065515005505 + 10065515005506.

It is an arithmetic number, because the mean of its divisors is an integer number (10065515005506).

Almost surely, 220131030011011 is an apocalyptic number.

20131030011011 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131030011011 is an equidigital number, since it uses as much as digits as its factorization.

20131030011011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 20131030011011 its reverse (11011003013102), we get a palindrome (31142033024113).

The spelling of 20131030011011 in words is "twenty trillion, one hundred thirty-one billion, thirty million, eleven thousand, eleven".