Base | Representation |
---|---|
bin | 1001001001111000111101… |
… | …11001001000110010000011 |
3 | 2122021111201002112201202112 |
4 | 10210330132321020302003 |
5 | 10114311322140323021 |
6 | 110452022330005535 |
7 | 4145263455522533 |
oct | 444743671106203 |
9 | 78244632481675 |
10 | 20131030011011 |
11 | 6461581698737 |
12 | 23116412768ab |
13 | b3046a6a272a |
14 | 4d84c04474c3 |
15 | 24d9c3357d5b |
hex | 124f1ee48c83 |
20131030011011 has 2 divisors, whose sum is σ = 20131030011012. Its totient is φ = 20131030011010.
The previous prime is 20131030010989. The next prime is 20131030011013. The reversal of 20131030011011 is 11011003013102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131030011011 - 214 = 20131029994627 is a prime.
Together with 20131030011013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20131030011013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065515005505 + 10065515005506.
It is an arithmetic number, because the mean of its divisors is an integer number (10065515005506).
Almost surely, 220131030011011 is an apocalyptic number.
20131030011011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131030011011 is an equidigital number, since it uses as much as digits as its factorization.
20131030011011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 20131030011011 its reverse (11011003013102), we get a palindrome (31142033024113).
The spelling of 20131030011011 in words is "twenty trillion, one hundred thirty-one billion, thirty million, eleven thousand, eleven".
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