Base | Representation |
---|---|
bin | 11101010010110110010… |
… | …011101111000000101101 |
3 | 21010110011122001112101012 |
4 | 131102312103233000231 |
5 | 230440313422234013 |
6 | 4140450142355005 |
7 | 265304401616342 |
oct | 35226623570055 |
9 | 7113148045335 |
10 | 2013103321133 |
11 | 706830385a03 |
12 | 2861a028ba65 |
13 | 117ab1170428 |
14 | 6d612c327c9 |
15 | 3757353d1a8 |
hex | 1d4b64ef02d |
2013103321133 has 2 divisors, whose sum is σ = 2013103321134. Its totient is φ = 2013103321132.
The previous prime is 2013103321127. The next prime is 2013103321193. The reversal of 2013103321133 is 3311233013102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2005288230724 + 7815090409 = 1416082^2 + 88403^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013103321133 - 212 = 2013103317037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013103321099 and 2013103321108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013103321193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006551660566 + 1006551660567.
It is an arithmetic number, because the mean of its divisors is an integer number (1006551660567).
Almost surely, 22013103321133 is an apocalyptic number.
It is an amenable number.
2013103321133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013103321133 is an equidigital number, since it uses as much as digits as its factorization.
2013103321133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 2013103321133 its reverse (3311233013102), we get a palindrome (5324336334235).
The spelling of 2013103321133 in words is "two trillion, thirteen billion, one hundred three million, three hundred twenty-one thousand, one hundred thirty-three".
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