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20131034281 is a prime number
BaseRepresentation
bin10010101111111001…
…110011010010101001
31220221222002111111021
4102233321303102221
5312212021044111
613125325532441
71311602653021
oct225771632251
956858074437
1020131034281
1185a0498016
123a99a14121
131b8a896107
14d8d874a81
157cc500d71
hex4afe734a9

20131034281 has 2 divisors, whose sum is σ = 20131034282. Its totient is φ = 20131034280.

The previous prime is 20131034267. The next prime is 20131034323. The reversal of 20131034281 is 18243013102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15228794025 + 4902240256 = 123405^2 + 70016^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20131034281 is a prime.

It is a super-2 number, since 2×201310342812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20131034251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065517140 + 10065517141.

It is an arithmetic number, because the mean of its divisors is an integer number (10065517141).

Almost surely, 220131034281 is an apocalyptic number.

It is an amenable number.

20131034281 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131034281 is an equidigital number, since it uses as much as digits as its factorization.

20131034281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 20131034281 its reverse (18243013102), we get a palindrome (38374047383).

The spelling of 20131034281 in words is "twenty billion, one hundred thirty-one million, thirty-four thousand, two hundred eighty-one".