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2013104020513 is a prime number
BaseRepresentation
bin11101010010110110010…
…110011001110000100001
321010110011200101001202011
4131102312112121300201
5230440314112124023
64140450205352521
7265304410561345
oct35226626316041
97113150331664
102013104020513
11706830813403
122861a0568741
13117ab1356871
146d612d75625
153757362a50d
hex1d4b6599c21

2013104020513 has 2 divisors, whose sum is σ = 2013104020514. Its totient is φ = 2013104020512.

The previous prime is 2013104020511. The next prime is 2013104020517. The reversal of 2013104020513 is 3150204013102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1521502514064 + 491601506449 = 1233492^2 + 701143^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013104020513 - 21 = 2013104020511 is a prime.

Together with 2013104020511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2013104020511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552010256 + 1006552010257.

It is an arithmetic number, because the mean of its divisors is an integer number (1006552010257).

Almost surely, 22013104020513 is an apocalyptic number.

It is an amenable number.

2013104020513 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013104020513 is an equidigital number, since it uses as much as digits as its factorization.

2013104020513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 2013104020513 its reverse (3150204013102), we get a palindrome (5163308033615).

The spelling of 2013104020513 in words is "two trillion, thirteen billion, one hundred four million, twenty thousand, five hundred thirteen".