Base | Representation |
---|---|
bin | 11101010010110110010… |
… | …111111001101000111111 |
3 | 21010110011201010000110212 |
4 | 131102312113321220333 |
5 | 230440314212210442 |
6 | 4140450222023035 |
7 | 265304414115344 |
oct | 35226627715077 |
9 | 7113151100425 |
10 | 2013104413247 |
11 | 706830a61484 |
12 | 2861a0717a7b |
13 | 117ab1463555 |
14 | 6d6130387cb |
15 | 375736a6a82 |
hex | 1d4b65f9a3f |
2013104413247 has 2 divisors, whose sum is σ = 2013104413248. Its totient is φ = 2013104413246.
The previous prime is 2013104413231. The next prime is 2013104413253. The reversal of 2013104413247 is 7423144013102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013104413247 - 24 = 2013104413231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013104413217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552206623 + 1006552206624.
It is an arithmetic number, because the mean of its divisors is an integer number (1006552206624).
Almost surely, 22013104413247 is an apocalyptic number.
2013104413247 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013104413247 is an equidigital number, since it uses as much as digits as its factorization.
2013104413247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 2013104413247 its reverse (7423144013102), we get a palindrome (9436248426349).
The spelling of 2013104413247 in words is "two trillion, thirteen billion, one hundred four million, four hundred thirteen thousand, two hundred forty-seven".
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